A number is divisible by 12 if it is divisible by 3 AND 4.
Remember:
1) If the sum of the digits of a number is divisible by 3 that number is divisible by 3. For example, 2130021 is divisible by 3 because 9, the sum of its digits (2 + 1 + 3 + 0 + 0 + 2 + 1 = 9), is divisible by 3.
2) If half of a number is an even number then that number is divisible by 4. For example, 72 is divisible by 4 because half of it, 36, is an even number. Also, if the last two digits of a number is divisible by 4 then that number is divisible by 4. As an example: 897232 is divisible by 4 because its last 2 digits; i.e. 32, is divisible by 4.
Q: Is 804 divisible by 12?
A: Yes, because it is divisible by 3 and 4:
8 + 0 + 4 = 12 where 12 is divisible by 3
AND
804 / 2 = 402 where 402 is an even number.
Practice:
Find a path from the START to the END passing only through numbers that are divisible by 12. Note that there is only one solution for this numerical maze.
Scroll down to check your solution!
Remember:
1) If the sum of the digits of a number is divisible by 3 that number is divisible by 3. For example, 2130021 is divisible by 3 because 9, the sum of its digits (2 + 1 + 3 + 0 + 0 + 2 + 1 = 9), is divisible by 3.
2) If half of a number is an even number then that number is divisible by 4. For example, 72 is divisible by 4 because half of it, 36, is an even number. Also, if the last two digits of a number is divisible by 4 then that number is divisible by 4. As an example: 897232 is divisible by 4 because its last 2 digits; i.e. 32, is divisible by 4.
Q: Is 804 divisible by 12?
A: Yes, because it is divisible by 3 and 4:
8 + 0 + 4 = 12 where 12 is divisible by 3
AND
804 / 2 = 402 where 402 is an even number.
Practice:
Find a path from the START to the END passing only through numbers that are divisible by 12. Note that there is only one solution for this numerical maze.
Scroll down to check your solution!
